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5(2z+3)=6(3z+2)-35
We move all terms to the left:
5(2z+3)-(6(3z+2)-35)=0
We multiply parentheses
10z-(6(3z+2)-35)+15=0
We calculate terms in parentheses: -(6(3z+2)-35), so:We get rid of parentheses
6(3z+2)-35
We multiply parentheses
18z+12-35
We add all the numbers together, and all the variables
18z-23
Back to the equation:
-(18z-23)
10z-18z+23+15=0
We add all the numbers together, and all the variables
-8z+38=0
We move all terms containing z to the left, all other terms to the right
-8z=-38
z=-38/-8
z=4+3/4
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