5(2f-1)+2(f+5)=5

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Solution for 5(2f-1)+2(f+5)=5 equation: 



5(2f-1)+2(f+5)=5

We move all terms to the left:

5(2f-1)+2(f+5)-(5)=0

We multiply parentheses

10f+2f-5+10-5=0

We add all the numbers together, and all the variables

12f=0

f=0/12

f=0

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