If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5n^2+42n+49=0
a = 5; b = 42; c = +49;
Δ = b2-4ac
Δ = 422-4·5·49
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-28}{2*5}=\frac{-70}{10} =-7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+28}{2*5}=\frac{-14}{10} =-1+2/5 $
| 2x+4/8=18)8 | | -10+3x=6x-13 | | n/4-5=-8 | | 125=20+42x | | 13j−11j+2j+2=14 | | 1.4x+2=23 | | -n/12=6 | | 2m-m-1=16 | | 4(x-8)+2x=-7+6x-5 | | 12w=8w+24 | | -4=5=s | | 3(3x+4)-5=9+-2 | | 6^x=57 | | 4(2m+5)-5m=29 | | 6x^2+28=4 | | 3-2x=-1,5x | | (x+12)=440 | | -5x-6(7x-7)=230 | | (7x−4)=21x−12 | | 4-(-x-8)=(1)/(2)(x+3) | | y4=2.7 | | 20=-4(m+8) | | (3x-5)^0+70=90 | | -4(3/4x-1/2)=-15 | | 354=6(38+c) | | 2(3w+4=50 | | –10h+7h=–3h | | 8x²–10x–3=0 | | 22y+1+y+11=180 | | -3f-7=8. | | y+5-2(-6y-1)=7(y-1) | | 20=–4(m+8) |