y+5-2(-6y-1)=7(y-1)

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Solution for y+5-2(-6y-1)=7(y-1) equation: 



y+5-2(-6y-1)=7(y-1)

We move all terms to the left:

y+5-2(-6y-1)-(7(y-1))=0

We multiply parentheses

y+12y-(7(y-1))+2+5=0



We calculate terms in parentheses: -(7(y-1)), so:

7(y-1)

We multiply parentheses

7y-7

Back to the equation:

-(7y-7)



We add all the numbers together, and all the variables

13y-(7y-7)+7=0

We get rid of parentheses

13y-7y+7+7=0

We add all the numbers together, and all the variables

6y+14=0

We move all terms containing y to the left, all other terms to the right

6y=-14

y=-14/6

y=-2+1/3

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