5n-(3n-1)=2(n+1)-1

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Solution for 5n-(3n-1)=2(n+1)-1 equation: 



5n-(3n-1)=2(n+1)-1

We move all terms to the left:

5n-(3n-1)-(2(n+1)-1)=0

We get rid of parentheses

5n-3n-(2(n+1)-1)+1=0



We calculate terms in parentheses: -(2(n+1)-1), so:

2(n+1)-1

We multiply parentheses

2n+2-1

We add all the numbers together, and all the variables

2n+1

Back to the equation:

-(2n+1)



We add all the numbers together, and all the variables

2n-(2n+1)+1=0

We get rid of parentheses

2n-2n-1+1=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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