(2y-3)/y+1=1

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Solution for (2y-3)/y+1=1 equation: 



(2y-3)/y+1=1

We move all terms to the left:

(2y-3)/y+1-(1)=0



Domain of the equation: y!=0

y∈R



We add all the numbers together, and all the variables

(2y-3)/y=0

We multiply all the terms by the denominator


(2y-3)=0

We get rid of parentheses

2y-3=0

We move all terms containing y to the left, all other terms to the right

2y=3

y=3/2

y=1+1/2

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