5m-3-2/m+3=-3

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Solution for 5m-3-2/m+3=-3 equation: 


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

5*m-(2/m)-3+3 = -3 // + 3

5*m-(2/m)-3+3+3 = 0

5*m-2*m^-1-3+3+3 = 0

5*m^1-2*m^-1+3*m^0 = 0

(5*m^2+3*m^1-2*m^0)/(m^1) = 0 // * m^2

m^1*(5*m^2+3*m^1-2*m^0) = 0

m^1

5*m^2+3*m-2 = 0

5*m^2+3*m-2 = 0

DELTA = 3^2-(-2*4*5)

DELTA = 49

DELTA > 0

m = (49^(1/2)-3)/(2*5) or m = (-49^(1/2)-3)/(2*5)

m = 2/5 or m = -1

m in { -1, 2/5} 

m in { -1, 2/5 }

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