1/12(4z+27)=1/4(2z+5)

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Solution for 1/12(4z+27)=1/4(2z+5) equation: 


z in (-oo:+oo)

(1/12)*(4*z+27) = (1/4)*(2*z+5) // - (1/4)*(2*z+5)

(1/12)*(4*z+27)-((1/4)*(2*z+5)) = 0

(1/12)*(4*z+27)+(-1/4)*(2*z+5) = 0

1/12*(4*z+27)-1/4*(2*z+5) = 0

1/12*(4*z+27)-1/4*(2*z+5) = 0

1-1/6*z = 0

1-1/6*z = 0

1-1/6*z = 0 // - 1

-1/6*z = -1 // : -1/6

z = -1/(-1/6)

z = 6

z = 6

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