5m(m=3)=(m)(5m-3)=36

Solution for 5m(m=3)=(m)(5m-3)=36 equation:

5m(m=3)=(m)(5m-3)=36

We move all terms to the left:

5m(m-(3))=0

We multiply parentheses

5m^2-15m=0

a = 5; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·5·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*5}=\frac{0}{10}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*5}=\frac{30}{10}
=3
$