4(3x+1)=4(x-2)

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Solution for 4(3x+1)=4(x-2) equation: 



4(3x+1)=4(x-2)

We move all terms to the left:

4(3x+1)-(4(x-2))=0

We multiply parentheses

12x-(4(x-2))+4=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We get rid of parentheses

12x-4x+8+4=0

We add all the numbers together, and all the variables

8x+12=0

We move all terms containing x to the left, all other terms to the right

8x=-12

x=-12/8

x=-1+1/2

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