5k+1=1/3(3-6k)+2

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Solution for 5k+1=1/3(3-6k)+2 equation: 



5k+1=1/3(3-6k)+2

We move all terms to the left:

5k+1-(1/3(3-6k)+2)=0



Domain of the equation: 3(3-6k)+2)!=0

k∈R



We add all the numbers together, and all the variables

5k-(1/3(-6k+3)+2)+1=0

We multiply all the terms by the denominator


5k*3(-6k+3)+1*3(-6k+3)+2)-(1+2)=0

We add all the numbers together, and all the variables

5k*3(-6k+3)+1*3(-6k+3)+2)-3=0

We add all the numbers together, and all the variables

5k*3(-6k+3)+1*3(-6k+3)=0

Wy multiply elements

15k^2(-+3k(-=0

We do not support ekpression: k^2(

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