4(5x+3)=4(5+4x)+3(1+2x)

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Solution for 4(5x+3)=4(5+4x)+3(1+2x) equation: 



4(5x+3)=4(5+4x)+3(1+2x)

We move all terms to the left:

4(5x+3)-(4(5+4x)+3(1+2x))=0

We add all the numbers together, and all the variables

4(5x+3)-(4(4x+5)+3(2x+1))=0

We multiply parentheses

20x-(4(4x+5)+3(2x+1))+12=0



We calculate terms in parentheses: -(4(4x+5)+3(2x+1)), so:

4(4x+5)+3(2x+1)

We multiply parentheses

16x+6x+20+3

We add all the numbers together, and all the variables

22x+23

Back to the equation:

-(22x+23)



We get rid of parentheses

20x-22x-23+12=0

We add all the numbers together, and all the variables

-2x-11=0

We move all terms containing x to the left, all other terms to the right

-2x=11

x=11/-2

x=-5+1/2

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