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5h-2(3/2h+2)=10
We move all terms to the left:
5h-2(3/2h+2)-(10)=0
Domain of the equation: 2h+2)!=0We multiply parentheses
h∈R
5h-6h-4-10=0
We add all the numbers together, and all the variables
-1h-14=0
We move all terms containing h to the left, all other terms to the right
-h=14
h=14/-1
h=-14
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