5(c-3)+6=4+c-13

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Solution for 5(c-3)+6=4+c-13 equation: 



5(c-3)+6=4+c-13

We move all terms to the left:

5(c-3)+6-(4+c-13)=0

We add all the numbers together, and all the variables

5(c-3)-(c-9)+6=0

We multiply parentheses

5c-(c-9)-15+6=0

We get rid of parentheses

5c-c+9-15+6=0

We add all the numbers together, and all the variables

4c=0

c=0/4

c=0

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