5c-(c+4)=10-2(c-8)

Solution for 5c-(c+4)=10-2(c-8) equation:

5c-(c+4)=10-2(c-8)

We move all terms to the left:

5c-(c+4)-(10-2(c-8))=0

We get rid of parentheses

5c-c-(10-2(c-8))-4=0


We calculate terms in parentheses: -(10-2(c-8)), so:

10-2(c-8)

determiningTheFunctionDomain
-2(c-8)+10

We multiply parentheses

-2c+16+10

We add all the numbers together, and all the variables

-2c+26

Back to the equation:

-(-2c+26)


We add all the numbers together, and all the variables

4c-(-2c+26)-4=0

We get rid of parentheses

4c+2c-26-4=0

We add all the numbers together, and all the variables

6c-30=0

We move all terms containing c to the left, all other terms to the right

6c=30

c=30/6

c=5