5c-(c+4)=10-2(c+8)

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Solution for 5c-(c+4)=10-2(c+8) equation: 



5c-(c+4)=10-2(c+8)

We move all terms to the left:

5c-(c+4)-(10-2(c+8))=0

We get rid of parentheses

5c-c-(10-2(c+8))-4=0



We calculate terms in parentheses: -(10-2(c+8)), so:

10-2(c+8)

determiningTheFunctionDomain
-2(c+8)+10

We multiply parentheses

-2c-16+10

We add all the numbers together, and all the variables

-2c-6

Back to the equation:

-(-2c-6)



We add all the numbers together, and all the variables

4c-(-2c-6)-4=0

We get rid of parentheses

4c+2c+6-4=0

We add all the numbers together, and all the variables

6c+2=0

We move all terms containing c to the left, all other terms to the right

6c=-2

c=-2/6

c=-1/3

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