30=3(3q+4)+2(q-2)

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Solution for 30=3(3q+4)+2(q-2) equation: 



30=3(3q+4)+2(q-2)

We move all terms to the left:

30-(3(3q+4)+2(q-2))=0



We calculate terms in parentheses: -(3(3q+4)+2(q-2)), so:

3(3q+4)+2(q-2)

We multiply parentheses

9q+2q+12-4

We add all the numbers together, and all the variables

11q+8

Back to the equation:

-(11q+8)



We get rid of parentheses

-11q-8+30=0

We add all the numbers together, and all the variables

-11q+22=0

We move all terms containing q to the left, all other terms to the right

-11q=-22

q=-22/-11

q=+2

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