6y-40=-8(y-2)

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Solution for 6y-40=-8(y-2) equation: 



6y-40=-8(y-2)

We move all terms to the left:

6y-40-(-8(y-2))=0



We calculate terms in parentheses: -(-8(y-2)), so:

-8(y-2)

We multiply parentheses

-8y+16

Back to the equation:

-(-8y+16)



We get rid of parentheses

6y+8y-16-40=0

We add all the numbers together, and all the variables

14y-56=0

We move all terms containing y to the left, all other terms to the right

14y=56

y=56/14

y=4

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