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5c+2-3c=-2(2c+4)
We move all terms to the left:
5c+2-3c-(-2(2c+4))=0
We add all the numbers together, and all the variables
2c-(-2(2c+4))+2=0
We calculate terms in parentheses: -(-2(2c+4)), so:We get rid of parentheses
-2(2c+4)
We multiply parentheses
-4c-8
Back to the equation:
-(-4c-8)
2c+4c+8+2=0
We add all the numbers together, and all the variables
6c+10=0
We move all terms containing c to the left, all other terms to the right
6c=-10
c=-10/6
c=-1+2/3
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