-10(v-4)-11=-7(v-5)+12

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Solution for -10(v-4)-11=-7(v-5)+12 equation: 



-10(v-4)-11=-7(v-5)+12

We move all terms to the left:

-10(v-4)-11-(-7(v-5)+12)=0

We multiply parentheses

-10v-(-7(v-5)+12)+40-11=0



We calculate terms in parentheses: -(-7(v-5)+12), so:

-7(v-5)+12

We multiply parentheses

-7v+35+12

We add all the numbers together, and all the variables

-7v+47

Back to the equation:

-(-7v+47)



We add all the numbers together, and all the variables

-10v-(-7v+47)+29=0

We get rid of parentheses

-10v+7v-47+29=0

We add all the numbers together, and all the variables

-3v-18=0

We move all terms containing v to the left, all other terms to the right

-3v=18

v=18/-3

v=-6

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