5b-4=6(b-2)

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Solution for 5b-4=6(b-2) equation: 



5b-4=6(b-2)

We move all terms to the left:

5b-4-(6(b-2))=0



We calculate terms in parentheses: -(6(b-2)), so:

6(b-2)

We multiply parentheses

6b-12

Back to the equation:

-(6b-12)



We get rid of parentheses

5b-6b+12-4=0

We add all the numbers together, and all the variables

-1b+8=0

We move all terms containing b to the left, all other terms to the right

-b=-8

b=-8/-1

b=+8

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