5(u-3)-5=-2(-7u+1)-u

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Solution for 5(u-3)-5=-2(-7u+1)-u equation: 



5(u-3)-5=-2(-7u+1)-u

We move all terms to the left:

5(u-3)-5-(-2(-7u+1)-u)=0

We multiply parentheses

5u-(-2(-7u+1)-u)-15-5=0



We calculate terms in parentheses: -(-2(-7u+1)-u), so:

-2(-7u+1)-u

We add all the numbers together, and all the variables

-1u-2(-7u+1)

We multiply parentheses

-1u+14u-2

We add all the numbers together, and all the variables

13u-2

Back to the equation:

-(13u-2)



We add all the numbers together, and all the variables

5u-(13u-2)-20=0

We get rid of parentheses

5u-13u+2-20=0

We add all the numbers together, and all the variables

-8u-18=0

We move all terms containing u to the left, all other terms to the right

-8u=18

u=18/-8

u=-2+1/4

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