5b+3b+2b/5b=10b/5b

Solution for 5b+3b+2b/5b=10b/5b equation:

5b+3b+2b/5b=10b/5b

We move all terms to the left:

5b+3b+2b/5b-(10b/5b)=0


Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



Domain of the equation: 5b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

5b+3b+2b/5b-(+10b/5b)=0

We add all the numbers together, and all the variables

8b+2b/5b-(+10b/5b)=0

We get rid of parentheses

8b+2b/5b-10b/5b=0

We multiply all the terms by the denominator


8b*5b+2b-10b=0

We add all the numbers together, and all the variables

-8b+8b*5b=0

Wy multiply elements

40b^2-8b=0

a = 40; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·40·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*40}=\frac{0}{80}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*40}=\frac{16}{80}
=1/5
$