-(2-3b)-b=6

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Solution for -(2-3b)-b=6 equation: 



-(2-3b)-b=6

We move all terms to the left:

-(2-3b)-b-(6)=0

We add all the numbers together, and all the variables

-(-3b+2)-b-6=0

We add all the numbers together, and all the variables

-1b-(-3b+2)-6=0

We get rid of parentheses

-1b+3b-2-6=0

We add all the numbers together, and all the variables

2b-8=0

We move all terms containing b to the left, all other terms to the right

2b=8

b=8/2

b=4

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