5b+2(b+4)=8(1-6b)

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Solution for 5b+2(b+4)=8(1-6b) equation: 



5b+2(b+4)=8(1-6b)

We move all terms to the left:

5b+2(b+4)-(8(1-6b))=0

We add all the numbers together, and all the variables

5b+2(b+4)-(8(-6b+1))=0

We multiply parentheses

5b+2b-(8(-6b+1))+8=0



We calculate terms in parentheses: -(8(-6b+1)), so:

8(-6b+1)

We multiply parentheses

-48b+8

Back to the equation:

-(-48b+8)



We add all the numbers together, and all the variables

7b-(-48b+8)+8=0

We get rid of parentheses

7b+48b-8+8=0

We add all the numbers together, and all the variables

55b=0

b=0/55

b=0

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