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(x+2)(3x+4)=(3x+7)(x+3)
We move all terms to the left:
(x+2)(3x+4)-((3x+7)(x+3))=0
We multiply parentheses ..
(+3x^2+4x+6x+8)-((3x+7)(x+3))=0
We calculate terms in parentheses: -((3x+7)(x+3)), so:We get rid of parentheses
(3x+7)(x+3)
We multiply parentheses ..
(+3x^2+9x+7x+21)
We get rid of parentheses
3x^2+9x+7x+21
We add all the numbers together, and all the variables
3x^2+16x+21
Back to the equation:
-(3x^2+16x+21)
3x^2-3x^2+4x+6x-16x+8-21=0
We add all the numbers together, and all the variables
-6x-13=0
We move all terms containing x to the left, all other terms to the right
-6x=13
x=13/-6
x=-2+1/6
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