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5a=-3+(3/5)a
We move all terms to the left:
5a-(-3+(3/5)a)=0
Domain of the equation: 5)a)!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
5a-(-3+(+3/5)a)=0
We multiply all the terms by the denominator
5a*5)a)-(-3+(+3=0
Wy multiply elements
25a^2+3=0
a = 25; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·25·3
Δ = -300
Delta is less than zero, so there is no solution for the equation
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