4(1-d)=3-(3d+5)

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Solution for 4(1-d)=3-(3d+5) equation: 



4(1-d)=3-(3d+5)

We move all terms to the left:

4(1-d)-(3-(3d+5))=0

We add all the numbers together, and all the variables

4(-1d+1)-(3-(3d+5))=0

We multiply parentheses

-4d-(3-(3d+5))+4=0



We calculate terms in parentheses: -(3-(3d+5)), so:

3-(3d+5)

determiningTheFunctionDomain
-(3d+5)+3

We get rid of parentheses

-3d-5+3

We add all the numbers together, and all the variables

-3d-2

Back to the equation:

-(-3d-2)



We get rid of parentheses

-4d+3d+2+4=0

We add all the numbers together, and all the variables

-1d+6=0

We move all terms containing d to the left, all other terms to the right

-d=-6

d=-6/-1

d=+6

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