5a/8a+6=3a/4a

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Solution for 5a/8a+6=3a/4a equation: 



5a/8a+6=3a/4a

We move all terms to the left:

5a/8a+6-(3a/4a)=0



Domain of the equation: 8a!=0

a!=0/8

a!=0

a∈R





Domain of the equation: 4a)!=0

a!=0/1

a!=0

a∈R



We add all the numbers together, and all the variables

5a/8a-(+3a/4a)+6=0

We get rid of parentheses

5a/8a-3a/4a+6=0

We calculate fractions


(-24a^2)/32a^2+20a^2/32a^2+6=0

We multiply all the terms by the denominator


(-24a^2)+20a^2+6*32a^2=0

We add all the numbers together, and all the variables

20a^2+(-24a^2)+6*32a^2=0

Wy multiply elements

20a^2+(-24a^2)+192a^2=0

We get rid of parentheses

20a^2-24a^2+192a^2=0

We add all the numbers together, and all the variables

188a^2=0

a = 188; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·188·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{376}=0$

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