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5=2+(1/3)x
We move all terms to the left:
5-(2+(1/3)x)=0
Domain of the equation: 3)x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(2+(+1/3)x)+5=0
We multiply all the terms by the denominator
-(2+(+1+5*3)x)=0
We calculate terms in parentheses: -(2+(+1+5*3)x), so:We get rid of parentheses
2+(+1+5*3)x
determiningTheFunctionDomain (+1+5*3)x+2
We add all the numbers together, and all the variables
16x+2
Back to the equation:
-(16x+2)
-16x-2=0
We move all terms containing x to the left, all other terms to the right
-16x=2
x=2/-16
x=-1/8
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