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5a-10=10a+12(-10)+10
We move all terms to the left:
5a-10-(10a+12(-10)+10)=0
We calculate terms in parentheses: -(10a+12(-10)+10), so:We get rid of parentheses
10a+12(-10)+10
determiningTheFunctionDomain 10a+10+12(-10)
We add all the numbers together, and all the variables
10a-110
Back to the equation:
-(10a-110)
5a-10a+110-10=0
We add all the numbers together, and all the variables
-5a+100=0
We move all terms containing a to the left, all other terms to the right
-5a=-100
a=-100/-5
a=+20
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