0a2-10=630

Solution for 0a2-10=630 equation:

0a^2-10=630

We move all terms to the left:

0a^2-10-(630)=0

We add all the numbers together, and all the variables

a^2-640=0

a = 1; b = 0; c = -640;
Δ = b2-4ac
Δ = 02-4·1·(-640)
Δ = 2560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2560}=\sqrt{256*10}=\sqrt{256}*\sqrt{10}=16\sqrt{10}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{10}}{2*1}=\frac{0-16\sqrt{10}}{2}
=-\frac{16\sqrt{10}}{2}
=-8\sqrt{10}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{10}}{2*1}=\frac{0+16\sqrt{10}}{2}
=\frac{16\sqrt{10}}{2}
=8\sqrt{10}
$