5=x(4-x)

Solution for 5=x(4-x) equation:

5=x(4-x)

We move all terms to the left:

5-(x(4-x))=0

We add all the numbers together, and all the variables

-(x(-1x+4))+5=0


We calculate terms in parentheses: -(x(-1x+4)), so:

x(-1x+4)

We multiply parentheses

-1x^2+4x

Back to the equation:

-(-1x^2+4x)


We get rid of parentheses

1x^2-4x+5=0

We add all the numbers together, and all the variables

x^2-4x+5=0

a = 1; b = -4; c = +5;
Δ = b2-4ac
Δ = -42-4·1·5
Δ = -4
Delta is less than zero, so there is no solution for the equation