4(d-2)+2=4d-2(2-d)

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Solution for 4(d-2)+2=4d-2(2-d) equation: 



4(d-2)+2=4d-2(2-d)

We move all terms to the left:

4(d-2)+2-(4d-2(2-d))=0

We add all the numbers together, and all the variables

4(d-2)-(4d-2(-1d+2))+2=0

We multiply parentheses

4d-(4d-2(-1d+2))-8+2=0



We calculate terms in parentheses: -(4d-2(-1d+2)), so:

4d-2(-1d+2)

We multiply parentheses

4d+2d-4

We add all the numbers together, and all the variables

6d-4

Back to the equation:

-(6d-4)



We add all the numbers together, and all the variables

4d-(6d-4)-6=0

We get rid of parentheses

4d-6d+4-6=0

We add all the numbers together, and all the variables

-2d-2=0

We move all terms containing d to the left, all other terms to the right

-2d=2

d=2/-2

d=-1

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