3-(.5)(4-s)=2+(0.25)(5+s)

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Solution for 3-(.5)(4-s)=2+(0.25)(5+s) equation:



3-(.5)(4-s)=2+(0.25)(5+s)
We move all terms to the left:
3-(.5)(4-s)-(2+(0.25)(5+s))=0
We add all the numbers together, and all the variables
-(0.5)(-1s+4)-(2+(0.25)(s+5))+3=0
We multiply parentheses ..
-(-0.5s+2)-(2+(0.25)(s+5))+3=0
We calculate terms in parentheses: -(2+(0.25)(s+5)), so:
2+(0.25)(s+5)
determiningTheFunctionDomain (0.25)(s+5)+2
We multiply parentheses ..
(+0.25s+1.25)+2
We add all the numbers together, and all the variables
(0.25s+1.25)+2
We get rid of parentheses
0.25s+1.25+2
We add all the numbers together, and all the variables
0.25s+3.25
Back to the equation:
-(0.25s+3.25)
We get rid of parentheses
0.5s-0.25s-2-3.25+3=0
We add all the numbers together, and all the variables
0.25s-2.25=0
We move all terms containing s to the left, all other terms to the right
0.25s=2.25
s=2.25/0.25
s=9

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