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5=7/2(3x+2
We move all terms to the left:
5-(7/2(3x+2)=0
Domain of the equation: 2(3x+2)+5!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
2(3x+2)!=-5
x∈R
-(7=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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