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5=4+(1/2)t
We move all terms to the left:
5-(4+(1/2)t)=0
Domain of the equation: 2)t)!=0We add all the numbers together, and all the variables
t!=0/1
t!=0
t∈R
-(4+(+1/2)t)+5=0
We multiply all the terms by the denominator
-(4+(+1+5*2)t)=0
We calculate terms in parentheses: -(4+(+1+5*2)t), so:We get rid of parentheses
4+(+1+5*2)t
determiningTheFunctionDomain (+1+5*2)t+4
We add all the numbers together, and all the variables
11t+4
Back to the equation:
-(11t+4)
-11t-4=0
We move all terms containing t to the left, all other terms to the right
-11t=4
t=4/-11
t=-4/11
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