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5/6x-1/5x=18
We move all terms to the left:
5/6x-1/5x-(18)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 5x!=0We calculate fractions
x!=0/5
x!=0
x∈R
25x/30x^2+(-6x)/30x^2-18=0
We multiply all the terms by the denominator
25x+(-6x)-18*30x^2=0
Wy multiply elements
-540x^2+25x+(-6x)=0
We get rid of parentheses
-540x^2+25x-6x=0
We add all the numbers together, and all the variables
-540x^2+19x=0
a = -540; b = 19; c = 0;
Δ = b2-4ac
Δ = 192-4·(-540)·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-19}{2*-540}=\frac{-38}{-1080} =19/540 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+19}{2*-540}=\frac{0}{-1080} =0 $
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