5=2/3(-3)+b

Solution for 5=2/3(-3)+b equation:

5=2/3(-3)+b

We move all terms to the left:

5-(2/3(-3)+b)=0


Domain of the equation: 3(-3)+b)!=0

b∈R


We multiply all the terms by the denominator


-(2+5*3(-3)+b)=0


We calculate terms in parentheses: -(2+5*3(-3)+b), so:

2+5*3(-3)+b

determiningTheFunctionDomain
b+2+5*3(-3)

We add all the numbers together, and all the variables

b-43

Back to the equation:

-(b-43)


We get rid of parentheses

-b+43=0

We add all the numbers together, and all the variables

-1b+43=0

We move all terms containing b to the left, all other terms to the right

-b=-43

b=-43/-1

b=+43