2x+(3x+2)+(3x+2)=68

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Solution for 2x+(3x+2)+(3x+2)=68 equation: 



2x+(3x+2)+(3x+2)=68

We move all terms to the left:

2x+(3x+2)+(3x+2)-(68)=0

We get rid of parentheses

2x+3x+3x+2+2-68=0

We add all the numbers together, and all the variables

8x-64=0

We move all terms containing x to the left, all other terms to the right

8x=64

x=64/8

x=8

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