5=15-10(q+5)

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Solution for 5=15-10(q+5) equation: 



5=15-10(q+5)

We move all terms to the left:

5-(15-10(q+5))=0



We calculate terms in parentheses: -(15-10(q+5)), so:

15-10(q+5)

determiningTheFunctionDomain
-10(q+5)+15

We multiply parentheses

-10q-50+15

We add all the numbers together, and all the variables

-10q-35

Back to the equation:

-(-10q-35)



We get rid of parentheses

10q+35+5=0

We add all the numbers together, and all the variables

10q+40=0

We move all terms containing q to the left, all other terms to the right

10q=-40

q=-40/10

q=-4

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