10=-2(b-11)

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Solution for 10=-2(b-11) equation: 



10=-2(b-11)

We move all terms to the left:

10-(-2(b-11))=0



We calculate terms in parentheses: -(-2(b-11)), so:

-2(b-11)

We multiply parentheses

-2b+22

Back to the equation:

-(-2b+22)



We get rid of parentheses

2b-22+10=0

We add all the numbers together, and all the variables

2b-12=0

We move all terms containing b to the left, all other terms to the right

2b=12

b=12/2

b=6

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