5=1/7(10x+28)

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Solution for 5=1/7(10x+28) equation: 



5=1/7(10x+28)

We move all terms to the left:

5-(1/7(10x+28))=0



Domain of the equation: 7(10x+28))!=0

x∈R



We multiply all the terms by the denominator


-(1+5*7(10x+28))=0



We calculate terms in parentheses: -(1+5*7(10x+28)), so:

1+5*7(10x+28)

determiningTheFunctionDomain
5*7(10x+28)+1

Wy multiply elements

35x(1+1

Back to the equation:

-(35x(1+1)



We add all the numbers together, and all the variables

-(35x2=0

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