10=3/7(4x+35)

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Solution for 10=3/7(4x+35) equation: 



10=3/7(4x+35)

We move all terms to the left:

10-(3/7(4x+35))=0



Domain of the equation: 7(4x+35))!=0

x∈R



We multiply all the terms by the denominator


-(3+10*7(4x+35))=0



We calculate terms in parentheses: -(3+10*7(4x+35)), so:

3+10*7(4x+35)

determiningTheFunctionDomain
10*7(4x+35)+3

Wy multiply elements

70x(4+3

Back to the equation:

-(70x(4+3)



We add all the numbers together, and all the variables

-(70x7=0

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