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5=-1/3c
We move all terms to the left:
5-(-1/3c)=0
Domain of the equation: 3c)!=0We get rid of parentheses
c!=0/1
c!=0
c∈R
1/3c+5=0
We multiply all the terms by the denominator
5*3c+1=0
Wy multiply elements
15c+1=0
We move all terms containing c to the left, all other terms to the right
15c=-1
c=-1/15
c=-1/15
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