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2x*x=3600
We move all terms to the left:
2x*x-(3600)=0
Wy multiply elements
2x^2-3600=0
a = 2; b = 0; c = -3600;
Δ = b2-4ac
Δ = 02-4·2·(-3600)
Δ = 28800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{28800}=\sqrt{14400*2}=\sqrt{14400}*\sqrt{2}=120\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120\sqrt{2}}{2*2}=\frac{0-120\sqrt{2}}{4} =-\frac{120\sqrt{2}}{4} =-30\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120\sqrt{2}}{2*2}=\frac{0+120\sqrt{2}}{4} =\frac{120\sqrt{2}}{4} =30\sqrt{2} $
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