5=(z+2)

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Solution for 5=(z+2) equation: 



5=(z+2)

We move all terms to the left:

5-((z+2))=0



We calculate terms in parentheses: -((z+2)), so:

(z+2)

We get rid of parentheses

z+2

Back to the equation:

-(z+2)



We get rid of parentheses

-z-2+5=0

We add all the numbers together, and all the variables

-1z+3=0

We move all terms containing z to the left, all other terms to the right

-z=-3

z=-3/-1

z=+3

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