2(3+2x)=5(x-4)

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Solution for 2(3+2x)=5(x-4) equation: 



2(3+2x)=5(x-4)

We move all terms to the left:

2(3+2x)-(5(x-4))=0

We add all the numbers together, and all the variables

2(2x+3)-(5(x-4))=0

We multiply parentheses

4x-(5(x-4))+6=0



We calculate terms in parentheses: -(5(x-4)), so:

5(x-4)

We multiply parentheses

5x-20

Back to the equation:

-(5x-20)



We get rid of parentheses

4x-5x+20+6=0

We add all the numbers together, and all the variables

-1x+26=0

We move all terms containing x to the left, all other terms to the right

-x=-26

x=-26/-1

x=+26

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