5(y-1)=3(2y-5)-(1-3y)6

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Solution for 5(y-1)=3(2y-5)-(1-3y)6 equation: 



5(y-1)=3(2y-5)-(1-3y)6

We move all terms to the left:

5(y-1)-(3(2y-5)-(1-3y)6)=0

We add all the numbers together, and all the variables

5(y-1)-(3(2y-5)-(-3y+1)6)=0

We multiply parentheses

5y-(3(2y-5)-(-3y+1)6)-5=0



We calculate terms in parentheses: -(3(2y-5)-(-3y+1)6), so:

3(2y-5)-(-3y+1)6

We multiply parentheses

6y+18y-15-6

We add all the numbers together, and all the variables

24y-21

Back to the equation:

-(24y-21)



We get rid of parentheses

5y-24y+21-5=0

We add all the numbers together, and all the variables

-19y+16=0

We move all terms containing y to the left, all other terms to the right

-19y=-16

y=-16/-19

y=16/19

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