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5=(3x-5)/2
We move all terms to the left:
5-((3x-5)/2)=0
We multiply all the terms by the denominator
-((3x-5)+5*2)=0
We calculate terms in parentheses: -((3x-5)+5*2), so:We get rid of parentheses
(3x-5)+5*2
We add all the numbers together, and all the variables
(3x-5)+10
We get rid of parentheses
3x-5+10
We add all the numbers together, and all the variables
3x+5
Back to the equation:
-(3x+5)
-3x-5=0
We move all terms containing x to the left, all other terms to the right
-3x=5
x=5/-3
x=-1+2/3
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